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Identify the correct statement
The greater the mass of a simple pendulum bob, the shorter is its frequency of oscillation
A simple pendulum with a bob mass $M$ swings with an angular amplitude of $40^o$. When its angular amplitude is $20^o$, the tension in the string is less than $Mg$ $\cos 20^o$
As the length of a simple pendulum is increases, the maximum velocity of the bob for the same amplitude, during its oscillation also increases
The fractional change in the time period of a pendulum on changing the temperature is independent of the length of the pendulum
Solution
$\mathrm{T}=2 \pi \sqrt{\frac{\ell}{\mathrm{g}}}$
$\mathrm{T}=2 \pi \sqrt{\frac{\ell_{0}(1+\alpha)}{\mathrm{g}}}$
Increase in temperature
$\frac{\Delta \mathrm{T}}{\mathrm{T}}=\frac{1^{1}}{2} \frac{\Delta \theta}{\theta}$ this has no term of lengths
